Math, asked by chelsea29, 8 months ago

pls tell this ans with full explanation ​

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Answered by Anonymous
3

 \sqrt[4]{81 {}^{ - 2} }

 {3}^{ - 2}

 \frac{1}{ {3}^{2} }

 \frac{1}{9}

Hope it helps you...........

Answered by Anonymous
0

 =  \sqrt[4]{ {81}^{ - 2} }  \\  =  \sqrt[4]{ \frac{1}{81} }  \\  =(  { \frac{1}{81} )}^{ \frac{1}{4} }  \\  = ( { \frac{1}{3} )}^{4}  \times  {}^{ \frac{1}{4} }  \\  =  \frac{1}{3}

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