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yes ,plz solve this question I also need ans of these question .
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Step-by-step explanation:
Sm/Sn = m/2[2a + (m-1)d]/n/2[2a + (n-1)d] = m^2/n^2
= 2a+(m-1)d/2a + (n-1)d =m/n
= 2an + mnd -nd = 2am + mnd - md
= 2an - 2am = nd -md
= 2a(n-m) = d(n-m)
= 2a = d
d=2a
Tm/Tn= a+ (m-1)d/a+ (n-1)d
= a+(m-1)2a/a+(n-1)2a
= a[1 +(m-1)2]/a[1+(n-1)2]
= 1+ 2m-2/1+ 2n -2
= 2m-1/2n-1
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Hope it helped.
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