Math, asked by barbie64992, 1 year ago

pls this question. ​

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Answered by Aaish26
0

yes ,plz solve this question I also need ans of these question .


SK6731: Solved
Aaish26: ok
Answered by SK6731
3

Answer:

Step-by-step explanation:

Sm/Sn = m/2[2a + (m-1)d]/n/2[2a + (n-1)d] = m^2/n^2

= 2a+(m-1)d/2a + (n-1)d =m/n

= 2an + mnd -nd = 2am + mnd - md

= 2an - 2am = nd -md

= 2a(n-m) = d(n-m)

= 2a = d

d=2a

Tm/Tn= a+ (m-1)d/a+ (n-1)d

= a+(m-1)2a/a+(n-1)2a

= a[1 +(m-1)2]/a[1+(n-1)2]

= 1+ 2m-2/1+ 2n -2

= 2m-1/2n-1

......

Hope it helped.

.......

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Aaish26: thanks
barbie64992: could u give a clear pic
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