pls try question number 3 fast
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HELLO DEAR,
given that:-
2sin theta -1=0
=> 2sin theta =1
=> sintheta=1/2
=> sin theta =sin30°
=> theta=30°
--------------------and----------------------
sectheta +tantheta
=> sec30° + tan 30°
=> 2/√3 + 1/√3
=> (2+1)/√3
=> 3/√3
=> √3
I HOPE ITS HELP YOU DEAR,
THANKS
given that:-
2sin theta -1=0
=> 2sin theta =1
=> sintheta=1/2
=> sin theta =sin30°
=> theta=30°
--------------------and----------------------
sectheta +tantheta
=> sec30° + tan 30°
=> 2/√3 + 1/√3
=> (2+1)/√3
=> 3/√3
=> √3
I HOPE ITS HELP YOU DEAR,
THANKS
ankitsinghgame:
thanks
welcome
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