Question

Pls try solving this!!!!!!!!!! ​

Answer 1

Answer:

a = 0, b = 4

Step-by-step explanation:

Given :

$\lim_{x \to 1} f(x) = f(1) = 4$

(i) Left Hand Limit :

$\lim_{x \to 1^-} f(x)$

$\lim_{x \to 1^-} (a + bx)$

$\Rightarrow (a + b)$

(ii) Right Hand Limit :

$\lim_{x \to 1^+} f(x)$

$\lim_{x \to 1^+} (b - ax)$

$\Rightarrow (b - a)$

But,

LHL = f(1) = 4 and RHL = f(1) = 4.

Thus,

a + b = 4 and b - a = 4

On solving both equations, we get

a + b = 4

-a + b = 4

----------------

     2b = 8

       b = 4

Place b = 4 in above equations, we get

⇒ a + b = 4

⇒ a + 4 = 4

⇒ a = 0

Therefore,

Positive values of a and b are 0 and 4.

Hope it helps!

Answer 2

Answer:

HEY Buddy here's ur answer