plse solve this question
Attachments:

Answers
Answered by
3
hope this helps you.....
Attachments:

Answered by
2
heya... here's ur answer is..
sin 45 = BC /AC
1/root2= BC / 150
BC = 150/root2
BC =75root 2
hence the width of the river is 75 root 2
(used this attachment )
sin 45 = BC /AC
1/root2= BC / 150
BC = 150/root2
BC =75root 2
hence the width of the river is 75 root 2
(used this attachment )
Attachments:

Similar questions
Math,
10 months ago
English,
10 months ago
Social Sciences,
1 year ago
Sociology,
1 year ago
English,
1 year ago