Question

Plss answer my question, urgent, I will mark u as brainliest.. Plssss​

Answer 1

The distance traveled by him is:

:

Let r = the rate the man walked

then

(r+.5) = 1 hr less rate

and

(r-1) = 3 hr more rate

:

:

let t = time he actually walked

then

(t-1) = time at the faster rate

and

(t+3) = time at the slower rate

:

distance for all three situations is the same (dist = rate * time):

;

actual dist = faster time dist

rt = (r+.5)(t-1)

rt = rt - r + .5t - .5

rt - rt + r - .5t = -.5

r - .5t = -.5

:

actual dist = slower time dist

rt = (r-1)(t+3)

rt = rt + 3r -t - 3

rt - rt - 3r + t = -3

-3r + t = -3

:

multiply the 1st equation by 2 and add to the above equation

2r - t = -1

-3r + t = -3

---------------eliminates t

-r = -4

r = 4 km/h is the actual walking rate

:

Find t using: r -.5t = -.5

4 - .5t = -.5

-.5t = -.5 - 4

-.5t = - 4.5

Multiply eq by -2

t = 9 hrs actual time

:

Dist = r*t

4 * 9 = 36 km

:

:

see if this is true; find the time of each scenario

36/4.5 = 8 hrs (1h less)

36/3 = 12 hrs (3hr more)

hope this helped u

BRAINLIEST

PLS

HOPE IT IS CORRECT I AM NOT SURE BUT SEEMS GOOD

Answer 2

speed of person was 4kmph and he travelled the distance of 28km