Question

plss answer this question plss
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Answer 1

Keep this in mind,

${ (\frac{x}{y}) }^{ - 1} = \frac{y}{x}$

$\huge\underbrace\mathcal\pink{Solution}$

$= {( {2}^{ - 1} + {3}^{ - 1} + {4}^{ - 1}) }^{ - 1} \\ = { (\frac{1}{2} + \frac{1}{3} + \frac{1}{4}) }^{ - 1} \\ = {( \frac{6 + 4 + 3}{12} )}^{ - 1} \\ = ( { \frac{13}{12} )}^{ - 1} \\ = \frac{12}{13}$

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