Plss brainly members where are you.
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Answered by
1
listen dude....
here R1 and R2 is in series so total R is 3+3 = 6 ohm..... and now this is parallel with R3 so here total resistance is 1/6 + 1/3= 1/2.....=2 ohm.
now this new resistance and R4 and R5 are now in series so here total resistance is 0.5+2+0.5= 3 ohm.......
now as we have to find the reading of ammeter so
i = v/R
= 3/3
=1 A
So reading of ammeter is 1 Ampere
here R1 and R2 is in series so total R is 3+3 = 6 ohm..... and now this is parallel with R3 so here total resistance is 1/6 + 1/3= 1/2.....=2 ohm.
now this new resistance and R4 and R5 are now in series so here total resistance is 0.5+2+0.5= 3 ohm.......
now as we have to find the reading of ammeter so
i = v/R
= 3/3
=1 A
So reading of ammeter is 1 Ampere
Answered by
4
Hello freind!!
Don't worry I'm here ....
R1 and R2 are in series
so
R' = R1 + R2
= 3 + 3
=6 ohm
now R' and R2 are in parallel
therefore
1/R" = 1/R' + 1/R3
= 1/6 + 1/3 = 1/2
=> R" = 1/2
now R",R4,R5 are in series
R"' = 0.5 +2+0.5 = 3 ohm
then we know by ohm law
I = V/R"'
= 3/3
=1 Amp
Plzz mark it as brainlist!!
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