Physics, asked by Riyaverma, 1 year ago

The K.E of a particle of mass m moving with speed v is given by K=1/2mv2.if the K.E of a particle moving along x axis varies with x as K (x)=9-x2 then the region in which particle lies is?

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vickeydey: why
vickeydey: now i am busy
Riyaverma: kk
vickeydey: ??
Riyaverma: if u r bzy then okk
vickeydey: can u just post more tough questions on physics like these
Riyaverma: sure
vickeydey: plsss i also love physics very much
vickeydey: i shall contact u tomorrow
vickeydey: ni8

Answers

Answered by vickeydey
58
we know that the KE of a body cannot be negative.
so it must be ≥0.
hence from the question we have
9-x^2≥0=>x≤|3|=>-3≤x≤3.
so the correct choice is (2).
Answered by manasvikodwani2005
2

Answer:

the answer is (2). Here is the complete solution. hope it will help

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