plss help me by this ( but pls dont write search from net or sorry)
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hope this helps...
plz check
plz check
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Firstly, sustitute the value of x ,
= 3 + √5 /2 + 2 / 3 + √5 now rationalise
= u get 3 +√5 + 2( 3-√5)
-----------------------
9-5
= u get 3 ''
so we got the first thing
\
we know formulae ...( a ³+ b³ )=( a + b) ³ - 3ab
Now sustitute in the values
hurray//
= 3 + √5 /2 + 2 / 3 + √5 now rationalise
= u get 3 +√5 + 2( 3-√5)
-----------------------
9-5
= u get 3 ''
so we got the first thing
\
we know formulae ...( a ³+ b³ )=( a + b) ³ - 3ab
Now sustitute in the values
hurray//
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