Question

Plss help out............​

Answer 1

Answer:

is the correct answer dear

Answer 2

Explanation:

Answer:

The Titanium plate will expand by 2.04 × 10⁻³ cm

Given:

Initial length (L₀) = 20 cm.

Initial temperature (T₀) = 25 °C

Coefficient of expansion = 8.5 × 10⁻⁶

Final temperature (T) = 37 °C

Explanation:

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From the formula of linear expansion we know that,

\bigstar\;\underline{\boxed{\sf \Delta L=L_{o}\;\alpha\;\Delta T}}★ΔL=LoαΔT

Here,

ΔL Denotes Increase/Decrease in length.

L₀ Denotes Initial length.

α Denotes coefficient of expansion.

ΔT Denotes Temperature difference.

Solving & Substituting the values,

\begin{gathered}\longrightarrow\sf \Delta L=L_{o}\;\alpha\;\bigg(T-T_{o}\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times \bigg(37-25\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times 12\\\\\\\\\longrightarrow\sf \Delta L=240\times 8.5\times 10^{-12}\\\\\\\\\longrightarrow\sf \Delta L=2040\times 10^{-6}\\\\\\\\\longrightarrow\sf \Delta L=2.04\times 10^{-3}\\\\\\\\\longrightarrow\large{\underline{\boxed{\red{\sf \Delta L=2.04\times 10^{-3}\;cm}}}}\end{gathered}⟶ΔL=Loα(T−To)⟶ΔL=20×(8.5×10−6)×(37−25)⟶ΔL=20×(8.5×10−6)×12⟶ΔL=240×8.5×10−12⟶ΔL=2040×10−6⟶ΔL=2.04×10−3⟶ΔL=2.04×10−3cm

∴ The Titanium plate will expand by 2.04 × 10⁻³ cm.

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