Math, asked by shrishtisahite303, 9 months ago

plss plss solve kr do




121ⁿmultiple1331²=11 ki power 9​

Attachments:

Answers

Answered by shubhasmita32sahoo
0

Answer:

n= 3/4 or 0.75

Step-by-step explanation:

121^n × 1331² = 11^9

(11²)^n × (11³)² = 11^9

11^2n × 11^6 = 11^9

2n × 6 = 9

12n = 9

n = 9/12 = 3/4 or 0.75

Similar questions