plss solve this ... i m unable how to do this .... pls help me
Attachments:
Answers
Answered by
1
ky²-6ky+8k =0
k ( y²-6y+8) =0
k[ y²-(4+2)y+8] =0
k(y²-4y-2y+8)=0
k[ y(y-4)-2(y-4)] =0
k(y-4)(y-2) =0
k ( y²-6y+8) =0
k[ y²-(4+2)y+8] =0
k(y²-4y-2y+8)=0
k[ y(y-4)-2(y-4)] =0
k(y-4)(y-2) =0
kritikarastogi:
can u pls tell why there is a zero in the equation
Similar questions