plss solve this ques
i will mark as brainlist also
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<OPQ = 90° [Angle between the tangent and the radius at the point of contact is 90°]
Given that triangle OPQ is an isosceles triangle.
So, OP = PQ.
Hence, <OQP = 45°.
pssatchith:
hope this helps:)
but how 45??
can you explain your answer please
since it is an isosceles triangle, sum of all the angles is 180. since angle qpo is 90 degree, the sum of other two angles is also 90(180-90).Hence angle oqp=90/2 =45 degree
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i cant unless someone else also answer but still thanks
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