Question

Plss solve thisss as soon as possible.....

Answer 1

Answer:

mast question hai nahi banega ok

Answer 2

Here,

q=+1μC =10^-6

Given:- AO=2m,

BO=1m

As shown in Fig,

Va-Vb=[q/(4πE0)][(1/AO)-(1/BO)]

9×10^9×10^-6[(1/2)-1]

45001

If position of B is changed as shown in Fig. value of

(Va-Vb)

shall remain the same. This is because electric potenitial is a scalar quantity and its value does not change with change in orientation of the charges.

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