plsss answer if u know .........
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x^2 + y^2 +z ^2 = ( x+ y + z) ^2 - 2 ( xy + yz + zx)
= 1^2 - 2 (-1)
= 1 +2 =3
x3 + y3 + z3 - 3xyz = (x + y + z)(x2 + y2 + z2 - xy - yz - zx)x3 + y3+z3 =
1×(3-(-1) + 3 (-1) = 4 -3 =1.......
This answer is 100% right
Thank u★★★
#ckc
= 1^2 - 2 (-1)
= 1 +2 =3
x3 + y3 + z3 - 3xyz = (x + y + z)(x2 + y2 + z2 - xy - yz - zx)x3 + y3+z3 =
1×(3-(-1) + 3 (-1) = 4 -3 =1.......
This answer is 100% right
Thank u★★★
#ckc
JinKazama1:
Put x = y = z = 1 and check
Right
yes. now it is edited
yes
You just edited it cheater.
What about u
Yes, @Chaitanya is right √√
Thank u bro
Wlcm √√
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