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iii) Soln:Given: length=10cm,breadth=8cm and Height =5cm
Therefore, Total surface area of a cuboid =2lb+2lh+2hb
=(2×10×8)cm+(2×10×5)cm+(2×5×8) cm
=160cm + 100cm + 80cm
=340cm³
v) soln :Here l=5½cm,b=4cm and h=10½
= l= 11cm , b=4cm and h= 21
Therefore, Total surface area of a cuboid=2lb+2lh+2hb
=(2×11×4) cm+(2×11×21)cm+(2×21×4) cm
=88cm +462cm+168cm
=718cm³
vi) soln : Given l=16,b=8cm and h=6cm
Therefore, Total surface area of a cuboid =2lb+2lh+2hb
=(2×16×8) cm + (2×16×6)cm + (2×6×8)cm
= 256cm + 192cm + 96cm
=544cm³
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