Question

plssss answer now guys...... it's urgent

Answer 1

multiply with cos* with lhs and in rhs break sin2* by (1-cos2*)

Answer 2

LHS
[tex] \frac{1+ sec (x)}{sec(x)} = \frac{1+ \frac{1}{cos(x)} }{\frac{1}{cos(x)}} \\ = \frac{cos(x)+1}{\frac{cos(x)}{cos(x)}} = cos(x)+1[/tex]
RHS
[tex] \frac{sin^2(x)}{1-cos(x)} = \frac{1-cos^2(x)}{1-cos(x)} \\ = \frac{1-cos^2(x)}{1-cos(x)} \\ = \frac{(1-cos(x))(1+cos(x))}{1-cos(x)} = 1 + cos(x)[/tex]
LHS = RHS
Hence proved