Plssss answer this question and i'll mark the correct one as the brainliest .
A boy runs for 10 min . at a uniform speed of 9 km/h . at what speed should he run for next 20 min so that the average speed comes out to be 12km/h.
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HeY !!!
speed of boy for 10 min is 9km/h
time :- 10min = 10/60 = 1/6hour
so , distance = speed ×time
=> 9×10/60 = 9/6 = 3/2km
•°• total time = 20 m = 20/60 = 1/3 hour
here given average speed * = 12km/h
Average speed = average distance/total time taken
12 = 3/2 + x/
12× = 3/2+ x/1/3
12×1/3 = 3 + 2x /2
4 ×2 = 3+2x
8 -3 = 2x
5 = 2x
x = 5/2 km
means after 10min at speed 9km/h boys cover 5/2km in time 10 min
hence after 10 min in fensing 10 min =1/6hour
speed = 5/2/1/6
speed = 15km/h
if boy run 15km/h after 10min in 10min then average speed should be 12km/h
*************************************
Hope it helps you !!!
@Rajukumar111
speed of boy for 10 min is 9km/h
time :- 10min = 10/60 = 1/6hour
so , distance = speed ×time
=> 9×10/60 = 9/6 = 3/2km
•°• total time = 20 m = 20/60 = 1/3 hour
here given average speed * = 12km/h
Average speed = average distance/total time taken
12 = 3/2 + x/
12× = 3/2+ x/1/3
12×1/3 = 3 + 2x /2
4 ×2 = 3+2x
8 -3 = 2x
5 = 2x
x = 5/2 km
means after 10min at speed 9km/h boys cover 5/2km in time 10 min
hence after 10 min in fensing 10 min =1/6hour
speed = 5/2/1/6
speed = 15km/h
if boy run 15km/h after 10min in 10min then average speed should be 12km/h
*************************************
Hope it helps you !!!
@Rajukumar111
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