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Let no. of tables be x
&no. of chairs be y
2x+y=9000 eq1
x+4y=8000 eq2
Multiply eq1 *1
and eq2*2
The eq. will become
2x+y=9000 eq3
2x+4y=16000 eq4
By subtracting these equations
We get:
y=1000
Put the value of y in eq2
we get:
x=4000
cost of 1 table=x=4000
cost of 1 chair=y=1000
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