Question

Plssss help to find the answer



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Answer 1

Answer:

Let no. of tables be x

&no. of chairs be y

2x+y=9000 eq1

x+4y=8000 eq2

Multiply eq1 *1

and eq2*2

The eq. will become

2x+y=9000 eq3

2x+4y=16000 eq4

By subtracting these equations

We get:

y=1000

Put the value of y in eq2

we get:

x=4000

cost of 1 table=x=4000

cost of 1 chair=y=1000