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a number is 6 more than two times another number .the sum of two numbers is 24 . find the no...
pranavjha9380:
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Let numbers are a and ( 2a + 6 ),
Given, sum of the numbers = 24
a + 2a + 6 = 24
3a = 24 - 6
3a = 18
![a = \frac{18}{3} \\ \\ \\ \boxed{ \: a = 6} a = \frac{18}{3} \\ \\ \\ \boxed{ \: a = 6}](https://tex.z-dn.net/?f=a+%3D++%5Cfrac%7B18%7D%7B3%7D++%5C%5C++%5C%5C++%5C%5C++%5Cboxed%7B+%5C%3A+a+%3D+6%7D)
Hence, numbers are
a = 6
2a + 6
=> 2( 6 ) + 6
=> 12 + 6
=> 18
Numbers : 6 and 18
Given, sum of the numbers = 24
a + 2a + 6 = 24
3a = 24 - 6
3a = 18
Hence, numbers are
a = 6
2a + 6
=> 2( 6 ) + 6
=> 12 + 6
=> 18
Numbers : 6 and 18
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