Question

Plssss solve this question.I'll mark u the brainliest.

Answer 1

Answer:

√3a²/4

Step-by-step explanation:

From figure:

⇒ ΔABD ≅ ΔACD

⇒ BD = DC

∴ BC = a

∴ BD = DC = a/2

In right angled ΔABD,

⇒ AD² = AB² - BD²

           = a² - (a/2)²

           = a² - a²/4

           = 3a²/4

AD = √3a/2.

Area of ΔABC:

⇒ 1/2 * BC * AD

⇒ 1/2 * a * √3a/2

⇒ √3a²/4.

Hope it helps!

Answer 2

Step-by-step explanation:

ΔABD ≅ ΔACD

BD = DC

BC = a

BD = DC = a/2

In right angled ΔABD,

AD² = AB² - BD²

a² - (a/2)²

a² - a²/4

3a²/4

AD = √3a/2.

Area of ΔABC:

1/2 * BC * AD

1/2 * a * √3a/2

√3a²/4.