a block of mass 2 kg is placed on a floor the coefficient of the static force is 0.4. if a force of 2.8 newton is applied on the block parallel to the floor, the force of friction between the block and the floor is
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the limit of static friction here is 8n but the force which is applied is less than 8n so friction will oppose applied force having magnitude equal to 2.8 newton
SShahnaz:
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