find the co-ordinates of points C and D
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thesavagekid:
wait , i do :)
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The answer is (C) .
Ans.
Triangle ABC is equilateral .
i.e., AB = BC = AC
Now , AB = 2a ( by distance formula )
i.e., BC = 2a .........(1)
Now , OB = a ( by distance formula ).....(2)
In triangle OBC ;
BC^2 = OB^2 + OC^2 (Pythagoras Theorem )
(2a)^2 = (a)^2 + OC^2
3(a^2) = OC^2
i.e., OC = a(root3)
i.e., coordinates of C = (0,+a(root3))
Similarly ;
coordinates of D = (0,-a(root3)) ....(because it is in the negative side of y-axis)
:)
Ans.
Triangle ABC is equilateral .
i.e., AB = BC = AC
Now , AB = 2a ( by distance formula )
i.e., BC = 2a .........(1)
Now , OB = a ( by distance formula ).....(2)
In triangle OBC ;
BC^2 = OB^2 + OC^2 (Pythagoras Theorem )
(2a)^2 = (a)^2 + OC^2
3(a^2) = OC^2
i.e., OC = a(root3)
i.e., coordinates of C = (0,+a(root3))
Similarly ;
coordinates of D = (0,-a(root3)) ....(because it is in the negative side of y-axis)
:)
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