Plssssssss answer it
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Lhs becomes [(1+cosα)/sinα]^2
={1+cosα}^2/sin^2α
(1+cosa)^2/(1-cos^2a)
1+cosa/1-cosa
={1+cosα}^2/sin^2α
(1+cosa)^2/(1-cos^2a)
1+cosa/1-cosa
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I have given the proof in the image
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