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urgent tmr exam detailed answer pls
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net resistance (R) = 5+8+12 = 25 ohms
voltage(V) = 6V
current(I) = V/R = 6/25 = 0.24A
READING OF AMMETER = 0.24 AMPERES
READING OF VOLTMETER = potential drop at 12 ohm resistor
potential drop (V) =IR = 0.24 × 12 = 2.88 V
reading of voltmeter = 2.88 V
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voltage(V) = 6V
current(I) = V/R = 6/25 = 0.24A
READING OF AMMETER = 0.24 AMPERES
READING OF VOLTMETER = potential drop at 12 ohm resistor
potential drop (V) =IR = 0.24 × 12 = 2.88 V
reading of voltmeter = 2.88 V
please follow me
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