plsz tell laat one question
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Given that HCF of (6,72) = 6. then find the LCM of (6,72)
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chitra079:
i said last one
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Ans Given that the remainder is (x + a) ⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a ⇒ (2k – 9)x + [10 – 8k + k2 ] = x + a On comparing both the sides, we get 2k – 9 = 1 ⇒ 2k = 10 ∴ k = 5 Also 10 – 8k + k2 = a ⇒ 10 – 8(5) + 52 = a ⇒ 10 – 40 + 25 = a ∴ a = – 5
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