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Answers
Answer:
Given :
A circuit has been provided in the question.
To find:
Ratio of potential drops along the 3 resistances i.e.
E1 : E2 : E3
Concept:
First we will find out the Individual resistance and then the net resistance of the circuit.
After this , we can try to find the potential drops along each resistance.
Calculation:
Resistance of R1 = V²/W
=> R1 = 200²/100
=> R1 = 400 ohms
Resistance of R2 :
=> R2 = 200²/100
=> R2 = 400 ohms
Resistance of R3:
=> R3 = 200²/10
=> R3 = 4000 ohm
Now net resistance is as follows :
R eq. = 4000/11 + 400
=> Req. = 8400/11 ohm.
Now, net current = V/(R eq.)
=> I = 200/(8400/11)
=> I = 2200/8400
=> I = 22/84 amperes
Potential drop along R1
= I × R1
=( 22/84 ) × 400
=8800/84
= 104. 76 volts
Since R2 and R3 are in parallel, they will have same potential Difference along the resistances.
∴ E2 = E3 = (200 - 104.76 )
=> E2 = E3 = 95.23 volts.
Required ratio :
E1 : E2 : E3
= (104.76) : (95.24) : (95.24)
= 1.099 : 1 : 1
Hence the required ratio is obtained .
hey friend!
Good question!
✔✔refer to the attachment please
