Question

plus tell this quarter answer and solution​

Answer 1

Step-by-step explanation:

Given :-

$\sf \: \dfrac{3}{7} \times ( \dfrac{5}{6} + \dfrac{12}{13}) = ( \dfrac{3}{7} \times \dfrac{5}{6}) + ( \dfrac{3}{7} \times \dfrac{12}{13})$

Solution :-

L.H.S

$\implies \dfrac{3}{7} \times ( \dfrac{5}{6} + \dfrac{12}{13})$

$\implies \dfrac{ \cancel3}{7} \times \dfrac{5}{ \cancel6} + \dfrac{3}{7} \times \dfrac{12}{13}$

$\implies \: \dfrac{5}{7 \times 2} + \dfrac{3 \times 12}{7 \times 13}$

$\implies \dfrac{5}{14} + \dfrac{36}{91}$

L.C.M of 14 and 91 is 182

$\implies \dfrac{65 + 72}{182} = \dfrac{137}{182}$

R.H.S

$\implies( \dfrac{ \cancel3}{7} \times \dfrac{5}{ \cancel6}) + ( \dfrac{3}{7} \times \dfrac{12}{13})$

$\implies \: \dfrac{5}{7 \times 2} + \dfrac{3 \times 12}{7 \times 13}$

$\implies \dfrac{5}{14} + \dfrac{36}{91}$

L.C.M of 14 and 91 is 182

$\implies \dfrac{65 + 72}{182} = \dfrac{137}{182}$

$\sf{\huge \therefore} \: L.H.S = R.H.S$

$\sf \bf Hence \: verified \: \dag$