Question

plxzzz solve....Indices....Thnk you

Answer 1

hope my ans helps you....

Answer 2

[tex]3^4^x = (81)^-^1 \\ 3^4^x = (3^4)^-^1 \\ 3^4^x = (3^-^4) \\4x = -4 \\ x = -4/4 = -1 \\ similarly 10^ \frac{1}{y} = 0.0001 \\ 10^ \frac{1}{y} = 10^-^4 \\ \frac{1}{y} = -4 \\ y = \frac{1}{-4} \\ therefore 2^-^x * 16^y = 2^-^(^-^1^) * 16^ \frac{-1}{4} \\ 2^-^x * 16^y = 2 * (2^4)^ \frac{-1}{4} \\ 2^-^x * 16^y = 2 * 2^-^1 =1 [/tex]