Question

plz....................................................
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Answer 1

Here,

$\angle \: A = 6x - 2$

&

$\angle \: B \: = 4x + 48$

as,

$\angle \: A = \angle \: B \: (alternate \: interior \: angle)$

$\implies \: 6x - 2 = 4x + 48$

$\implies \: 4x = 50$

$\implies \: x = 12.5 \degree$

so,

$\angle \: A = 6x - 2 = 6 \times 12.5 - 2$

$= 75 - 2$

$= 73 \degree$

Answer 2

Answer:

Here,

\angle \: A = 6x - 2∠A=6x−2

&

\angle \: B \: = 4x + 48∠B=4x+48

as,

\angle \: A = \angle \: B \: (alternate \: interior \: angle)∠A=∠B(alternateinteriorangle)

\implies \: 6x - 2 = 4x + 48⟹6x−2=4x+48

\implies \: 4x = 50⟹4x=50

\implies \: x = 12.5 \degree⟹x=12.5°

so,

\angle \: A = 6x - 2 = 6 \times 12.5 - 2∠A=6x−2=6×12.5−2

= 75 - 2=75−2

= 73 \degree=73°