Question

plz aanswer this soon

Answer 1

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$\underline{SOLUTION}$ ➡

$[(3 - 2 \sqrt{2} ) - ( \frac{1}{3 - 2 \sqrt{2} } ) ]{}^{3}$

$= [ \frac{(3 - 2 \sqrt{2} ) {}^{2} - 1}{3 - 2 \sqrt{2} } ] {}^{3}$

$= [ \frac{9 - 12 \sqrt{2} + 8 - 1}{3 - 2 \sqrt{2} } ]{}^{3} \\ \\ = [ \frac{16 - 12 \sqrt{2} }{3 - 2 \sqrt{2} } ] {}^{3} \\ \\ = [\frac{(16 - 12 \sqrt{2})(3 + 2 \sqrt{2} }{(3 - 2 \sqrt{2} )(3 +2 \sqrt{2}) }] {}^{3} \\ \\ = [ \frac{16(3 + 2 \sqrt{2} ) - 12 \sqrt{2} (3 + 2 \sqrt{2} )}{(3) {}^{2} -( 2 \sqrt{2}) {}^{2} } ] {}^{3} \\ \\ = [ \frac{48 + 32 \sqrt{2} - 36 \sqrt{2} - 48}{9 - 8} ] {}^{3} \\ \\ = [ \frac{ - 4 \sqrt{2} }{1} ] {}^{3} \\ \\ = [ - 4 \sqrt{2} ]{}^{3} \\ \\ = - 128 \sqrt{2}$

$\underline{ANSWER}$ ➡ $\boxed{- 128 \sqrt{2}}$

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