Question

plz ans anyone
it's argent​

Answer 1

Answer:

this is answer.

are you understand this word problem?

Answer 2

$\huge \fbox \purple{Answer:}$

$\sf \colorbox{lightgreen} {\red★ \: \: Here}$

$r = 12 \: cm \:$

$= 120 \: degrees$

$\sf \colorbox{pink} {\red⇒The Area of the Sector OAB}$

$\frac{120}{360} \times \pi {r}^{2}$

Look at the pic Left Side

$= \frac{1}{3} \times 3.14 \times (12 {)}^{2} \: {cm}^{2} = 150.72 \: {cm}^{2}$

$AB = 2 AM = 2 \times O A \times \frac{AM}{O A }$

$= 2 \times 12 \times sin \: 60° = \sqrt[12]{3} \: cm$

$O M = OA \times \frac{O M}{OA}$

$= 12 \: cos \: 60° = 12 \times \frac{1}{2} = 6 \: cm$

Look at the pic Right side

$\sf \colorbox{pink} {\red⇒The Area of the }$

$∆OAB = \frac{1}{2} \times AB \times OM$

$= \frac{1}{2} \times \sqrt[12]{3} \: \times \: 6 \: {cm}^{2}$

$= 36 \times 1.73 \: {cm}^{2} = 62.28 \: {cm}^{2}$

The Area of the Segment ( shaded ) Made by the Chord AB

= The Area of the Sector OAB - The area of ∆OAB

$= (150.72 - 62.28) \: {cm}^{2}$

$= 88.44 \: {cm}^{2}$

$\\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$