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Hey !!
cos¢ + sin¢ = √2
(cos¢ + sin¢)² = (√2)² ➡ Squaring on both side
cos²¢ + sin²¢ + 2sin¢ ×cos¢ = 2
1 + 2sin¢ ×cos¢ = 2
sin2¢ = 1
sin2¢ = sin90°
¢ = 45°
hence , cos3¢ = cos3×45°
= cos135°
= cos(90° + 45° )
= -sin45°
= - 1/√2 Answer ✔
_________________________
Hope it helps you !!
@Rajukumar111
cos¢ + sin¢ = √2
(cos¢ + sin¢)² = (√2)² ➡ Squaring on both side
cos²¢ + sin²¢ + 2sin¢ ×cos¢ = 2
1 + 2sin¢ ×cos¢ = 2
sin2¢ = 1
sin2¢ = sin90°
¢ = 45°
hence , cos3¢ = cos3×45°
= cos135°
= cos(90° + 45° )
= -sin45°
= - 1/√2 Answer ✔
_________________________
Hope it helps you !!
@Rajukumar111
Aniket11111111:
Yes it helped me
Thanks
bt the answer is -1/√2
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