plz ans...I will mark brainliest and plz in a way plz ...
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✔hey there!!
Given that :
=> y /1 = {√(a+2b) + √(a-2b)} /{√(a+2b) -√(a-2b)}
Now applying Componendo and divendendo :
=> y+1/y-1 = 2√(a+2b) /2√(a-2b)
=> (y+1)/(y-1) = √a+2b/√a-2b
Now squaring both sides we get,
=>( y+1)²/(y-1)² = a+2b/a-2b
By cross multiplication :
=> (y²+2y+1)(a-2b) = (y²-2y+1)(a+2b)
=>ay²-2by²+2ay-4by+a-2b =ay²+2by²-2ay-4by+a+2b
Cancel out same sign from both the sides.
=> -2by²+2ay-2b = 2by²-2ay+2b
=> now collect the like terms :
=> -4by² +4ay -4b =0
Divide by -4 we get the required result,
=> by² - ay + b (proved)
_______________________________________
hope it will help u
Given that :
=> y /1 = {√(a+2b) + √(a-2b)} /{√(a+2b) -√(a-2b)}
Now applying Componendo and divendendo :
=> y+1/y-1 = 2√(a+2b) /2√(a-2b)
=> (y+1)/(y-1) = √a+2b/√a-2b
Now squaring both sides we get,
=>( y+1)²/(y-1)² = a+2b/a-2b
By cross multiplication :
=> (y²+2y+1)(a-2b) = (y²-2y+1)(a+2b)
=>ay²-2by²+2ay-4by+a-2b =ay²+2by²-2ay-4by+a+2b
Cancel out same sign from both the sides.
=> -2by²+2ay-2b = 2by²-2ay+2b
=> now collect the like terms :
=> -4by² +4ay -4b =0
Divide by -4 we get the required result,
=> by² - ay + b (proved)
_______________________________________
hope it will help u
urvshi1203:
but what he did in 5th and 6th step I cant understand
nooo after that...after transposing a to other side
toh root kahan gya
ya ya I understood now
thx a lot
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★ THERE IS YOURS SOLUTION ★
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HOPE IT HELPS ^_^
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hey!!
I cant understand the 5th and 6th step can u explain???
+2ab & - 2ab cancelled
yes.
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