Question

Plz ans the given Q

Answer 1

a=0
b=2
your question is solved above... check it

Answer 2

$\frac{ \sqrt{7} + \sqrt{5} }{ \sqrt{7} - \sqrt{5} } - \frac{ \sqrt{7} - \sqrt{5} }{ \sqrt{7} + \sqrt{5} } = a + \sqrt{35} b$
$\huge \textbf{LHS}$

$= \frac{ \sqrt{7} + \sqrt{5} }{ \sqrt{7} - \sqrt{5} } - \frac{ \sqrt{7} - \sqrt{5} }{ \sqrt{7} + \sqrt{5} } \\ \\ = \frac{ (\sqrt{7} + \sqrt{5})( \sqrt{7} + \sqrt{5}) }{( \sqrt{7} - \sqrt{5})( \sqrt{7} + \sqrt{5} )} - \frac{( \sqrt{7} - \sqrt{5})( \sqrt{7} - \sqrt{5} ) }{( \sqrt{7} + \sqrt{5} )( \sqrt{7} - \sqrt{5} )} \\ \\ = \frac{7 + \sqrt{35} + \sqrt{35} + 5 }{7 - 5} - \frac{7 - \sqrt{35} - \sqrt{35} + 5 }{7 - 5} \\ \\ = \frac{12 + 2 \sqrt{35} }{2} - \frac{12 - 2 \sqrt{35} }{2} \\ \\ = \frac{12 + 2 \sqrt{35} - 12 + 2 \sqrt{35} }{2} \\ \\ = \frac{ 4 \sqrt{35} }{2} \\ \\ = 2 \sqrt{35}\\ \\ \\ \\ \\ on \: comparing \: with \: a + b \sqrt{35} \\ \\ a = 0 \\ and \: b = 2$