Question

plz ans this question
I really need it
class 9​

Answer 1

Answer:

option B will be correct but recheck it ❤️

Answer 2

Answer:-------

$(2x - 1) \\ = > 2x = 1 \\ = > x = \frac{1}{2} \\ = > 2 {x}^{3} + 11 {x}^{2} + 4x + k = 0 \\ = > 2 \times ( { \frac{1}{2}) }^{3} + 11 \times { \frac{1}{2} }^{2} + 4 \times \frac{1}{2} + k = 0 \\ = > 2 \times \frac{1}{8} + \frac{11}{4} + 2 + k = 0 \\ = > \frac{1}{4} + \frac{11}{4} + \frac{8}{4} + k = 0 \\ = > \frac{20}{4} + k = 0 \\ = > k = - 5$