Question

plz ans this question which is given in attachment

Answer 1

1st find area of ABC triangle using half of base of height.
Next, taking BC=x , find the area as 1/2* x* 10.
Equate both of them. You will get value of x.
1/2*8*6=1/2*x*10
x=24/5
BD=x=24/5
Then in BDC apply Pythagoras theorem to find DC .
In triangle BDC,
(BC)^2= (BD)^2 + (DC)^2
Solve to find DC.
DC=√(36-(24/5)^2)=3.6
Area=1/2*3.6*(24/5)
= 8.64
Again use formula of area of the triangle in BDC.
You are done. Hurray!!