Plz ans this question with steps...
Answers
don't know brother. sorry 't help you
Answer:
Sorry Mai diagram provide Nahi kr paya
Step-by-step explanation:
Let's first draw a rough diagram
To construct A ABC, we first need to find angleC
Finding angleC
In ∆ ABC
angleA + angleB + angleC = 180° (Sum of angles of a triangle is 180°)
105° + 45° + angleC = 180°
150° + angleC = 180°
angleC = 180° - 150°
angleC = 30°
Steps to draw A ABC
1. Draw base BC of side 7 cm
2. Draw 2 B = 45°
3. Draw 2 C = 30°
4. Let point A be the point where the two rays intersect
:: ∆ABC is the required triangle
Now, we need to make a triangle which is 4/3 times its size
: Scale :. Scale factor 4/3 >1
Steps of construction
1. Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.
2. Mark 4 (the greater of 4 and 3 in ) points
B¹, B², B³, B⁴ on BX so that BB, = B,B² = B²B³ = B³B⁴
3. Join B³C (3rd point as 3 is smaller in 4/3) and draw a line through B⁴ parallel to B³C, to intersect BC
extended at C'.
4. Draw a line through C' parallel to the line AC to intersect AB extended at A'.
Thus, A A'BC' is the required triangle
Justification
Since scale factor is ,4/3
we need to prove A'B /AB =A'C'/ AC= BC/' BC = 4/ 3
By construction,
BC'/ BC= BB⁴ /BB³ =4/3. eq 1
Also, A'C' is parallel to AC
So, they will make the same angle with line BC
therefore. angle A'C'B = angle ACB
(Corresponding angles). (2)
Now,
In ∆ A'BC' and ∆ABC
angle B = angleB (Common)
ZA'C'B = 2 ACB (From (2)).
A A'BC' ~ A ABC (AA Similarity)
Since corresponding sides of 45 similar triangles are in the same ratio B¹
A'B/AB=A'C'/AC=BC¹/BC
So, A¹B/AB=A¹C¹/BC=BC¹/BC=4/3
Thus, our construction is justified