Question

PLZ ANS WITH PROCESS​

Answer 1

Answer:

x=2

refer to the attachment for explaination

Answer 2

→ Find value of x

${6}^{2x + 1} \div 36 = {6}^{3}$

${6}^{2x + 1} \div {6}^{2}$

$\frac{6 {}^{2x + 1} }{6 {}^{2} } = {6}^{3}$

$\frac{ {a}^{m} }{a {}^{n} } = {a}^{m - n}$

${6}^{2x +1 - 2 } = {6}^{3}$

${6}^{2x - 1} = {6}^{3}$

$bases \: are \: same \: compare \: those \: power$

$2x - 1 = 3$

$2x = 3 + 1$

$2x = 4$

$x = \frac{4}{2}$

$x = 2$