Question

plz anser it fast .. with solution

Answer 1

Heya

∆ By factor theorem, all the numbers from { 1 ... to 100 } are roots of the resultant polynomial

● Further, by root - coefficient relation, we have :

$coeff( {x}^{99} ) = - (1 + 2 + ... + 100)$

$= > coeff( {x}^{99} ) = - 5050$

♀ For the above calculation, use the A.P. formula, [ n( n - 1 ) / 2 ]

Hence, the desired coefficient is -5500 and the correct option is (c)