Question

plz answee yhis question it's really urgent

Answer 1

Hey Mate :

Solution :
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$f(x) = 2 |x| + |x - 2| \: \: \: at \: x = 1 \\ = diff \: with \: respect \: to \: x \\ = 2 \frac{d}{dx} x + \frac{d}{dx} (x + 2) \\ = 2 + (1 + 0) \\ = 2 + 1 \\ = 3 \\ \\ now \\ f(x) = 2 |x| + |x - 2| \\ \\by \: putting \: x = 1 \\ = > f(1) = 2 |1| + |1 - 2| \\ = > f(1) = 2 + | - 1| \\ = > f(1) = 2 + 1 \\ = > f(1) = 3 \\ \\ proved. \\ \\ нσρє ιт нєℓρѕ уσυ.... мαяк мє αѕ вяαιиℓιєѕт..$

Answer 2

for solution refer attachment