Question

Plz answer.............................................

Answer 1

Step-by-step explanation:

$\sqrt{3 {x}^{2}+6 } =9$

Squaring both sides

3xˆ2+6=81

3xˆ2=81-6

3xˆ2=75

Xˆ2=75/3

Xˆ2=25

Taking square root

X=5

$6 {x}^{2}- \sqrt{2}x-2=0</p><p>$

By formula method

$X=\frac{-b +- \sqrt{ {b}^{2}-4ac } }{2a}$

$x= \frac{ \sqrt{2}+- \sqrt{2+48} }{12}$

$x = \frac{ \sqrt{2}+-5 \sqrt{2} }{12}$

Taking positive sign

$X= \frac{ \sqrt{2}+5 \sqrt{2} }{12}$

$X= \frac{6 \sqrt{2} }{12}</p><p>$

$X= \frac{ \sqrt{2} }{2}$

Taking negative sign

$X= \frac{ \sqrt{2}-5 \sqrt{2} }{12}$

$X= \frac{-4 \sqrt{2} }{12}$

$X= \frac{- \sqrt{2} }{3}$