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BCD =90(angle in a semicircle)
DAC=DBC(angle in a same segments)
BCD+DBC+BDC=180
90+x+2x=180
3x=90
x=30
Hope it helps....
please mark me as brainliest answer.....
DAC=DBC(angle in a same segments)
BCD+DBC+BDC=180
90+x+2x=180
3x=90
x=30
Hope it helps....
please mark me as brainliest answer.....
surekhapatel03p26of0:
thanks
Answered by
2
angle DAC = X
So, Angle DBC = X (Angle of same segment)
In triangle BDC
angle DCB = 90° (Angle of semi circle)
Angle DBC+BDC+BCD =180°
X+2X+90°=180°
3X + 90° =180°
3X = 90°
X = 30°
So, Angle DBC = X (Angle of same segment)
In triangle BDC
angle DCB = 90° (Angle of semi circle)
Angle DBC+BDC+BCD =180°
X+2X+90°=180°
3X + 90° =180°
3X = 90°
X = 30°
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