plz answer 3rd question .. i will definitely Mark as brainliest
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Angle BCA = 180 - (105+24) = 51
Since BC || DE, Angle CED = Angle BCA
i.e., y = 51°
Since AB || CD, Angle BAC = Angle ECD = 24
From ∆ABC, 51 + 3x + 24 = 180
x = 35°
Since BC || DE, Angle CED = Angle BCA
i.e., y = 51°
Since AB || CD, Angle BAC = Angle ECD = 24
From ∆ABC, 51 + 3x + 24 = 180
x = 35°
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