Question

plz answer 42 question 15 marks . no spamming

Answer 1

Let
sides of triangle be a,b and c resp
area of triangle be ∆
by heron's formula
area of triangle ∆
= √s(s-a)(s-b)(s-c)
where s = a+b+c/2
each side is increased by 200
thus new sides became a+200/100*a = 3a
à=3a
same as 3b,3c
and new s = 3 old s
thus
new area = √3s(3s-3a)(3s-3b)(3s-3c)
= 9√s(s-a)(s-b)(s-c)
= 9∆
let area increased by x%
∆+X/100*∆ = 9∆
thus X = 800%
area of triangle increased by 800%

Answer 2

800%

is the correct answer

hope it helps you