Question

plz answer 5 6 7 8 9

Answer 1

8)  in quad ABOE,
  angle A is 90 degree(angle in a semicircle)
  angle A +angleB+angleO+angleE=360degree
   so,angleOEA= 85 degree
    so , angleOED=95 degree(linear pair)
 
        also angle EOC = 40 degree(linear pair)
          now by angle sum property in triangle EOC,
        EDO= 45 degree....
 
               HOPE IT HELPED
                   THUMBS UP!!!

Answer 2

6) Construction- Join BO and CO ( O is center of circle)
Proof- angle BOC= 60 ( angle subtended by an arc at the center of a circle is twice the angle subtended by the same arc on the remaining part of the circle)
BO=CO=radius of circle
BOC is an isosceles triangle
angle CBO=angle BCO ( angle opposite two equal sides of an isosceles triangle are equal)
2angleCBO+angle BOC=180(Angle Sum Property)
2angle CBO=120
angle CBO= 60
angle BCO=60 (angle CBO=BCO)
BOC is an equilateral triangle
BO=CO=BC
BUT BO=CO= radius
So, BC= radius