Math, asked by yashtyagi1, 1 year ago

plz answer ☝️above question

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Answered by sijasubbiah
1
Hey

Here is your answer

Let the speed of the car be C kmph
Let the speed of the train be T kmph

4 hours = 250 km / T kmph + (370 - 250) km / C kmph

         4 = 250/T + 120/C  -- equation 1

4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph
       258/60 = 4.3 = 130 / T + 240 / C      --- equation 2

Multiply equation 1 by 2 and subtract equation 2 from it.

       8 - 4.3 = 500/T - 130/T + 240/C - 240/C

       3.7 = 370 / T

       T = 370/3.7 = 100 kmph

Substitute the value of T in equation 1 to get,

       4 = 250/T + 120/C  -- equation 1
       4 = 250/100 + 120/C
       4 - 2.5 = 120/C

       C = 120/1.5 = 80 kmph

The train runs at 100 kmph and the car runs at 80 kmph

Hope it helps you!

yashtyagi1: means
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