plz answer ☝️above question
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Hey
Here is your answer
Let the speed of the car be C kmph
Let the speed of the train be T kmph
4 hours = 250 km / T kmph + (370 - 250) km / C kmph
4 = 250/T + 120/C -- equation 1
4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph
258/60 = 4.3 = 130 / T + 240 / C --- equation 2
Multiply equation 1 by 2 and subtract equation 2 from it.
8 - 4.3 = 500/T - 130/T + 240/C - 240/C
3.7 = 370 / T
T = 370/3.7 = 100 kmph
Substitute the value of T in equation 1 to get,
4 = 250/T + 120/C -- equation 1
4 = 250/100 + 120/C
4 - 2.5 = 120/C
C = 120/1.5 = 80 kmph
The train runs at 100 kmph and the car runs at 80 kmph
Hope it helps you!
Here is your answer
Let the speed of the car be C kmph
Let the speed of the train be T kmph
4 hours = 250 km / T kmph + (370 - 250) km / C kmph
4 = 250/T + 120/C -- equation 1
4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph
258/60 = 4.3 = 130 / T + 240 / C --- equation 2
Multiply equation 1 by 2 and subtract equation 2 from it.
8 - 4.3 = 500/T - 130/T + 240/C - 240/C
3.7 = 370 / T
T = 370/3.7 = 100 kmph
Substitute the value of T in equation 1 to get,
4 = 250/T + 120/C -- equation 1
4 = 250/100 + 120/C
4 - 2.5 = 120/C
C = 120/1.5 = 80 kmph
The train runs at 100 kmph and the car runs at 80 kmph
Hope it helps you!
yashtyagi1:
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