Question

plz answer all the reactions ​

Answer 1

$\displaystyle\sf{(a)\:B(OH)_3+NH_3\longrightarrow BN+3H_2O$

$\displaystyle\sf{(b)\:Na_2B_4O_7+H_2SO_4+H_2O\longrightarrow H_3BO_3+Na_2SO_4$

$\displaystyle\sf{(c)\:B_2H_6+2NaOH+2H_2O\longrightarrow 2Na[B(OH)_4]+2H_2$

$\displaystyle\sf{(d)\:B_2H_6+6CH_3OH\longrightarrow 2B(OCH_3)_3+6H_2$

$\displaystyle\sf{(e)\:2BF_3+3H_2O\longrightarrow H_3BO_3+HBF_4+2HF$

$\displaystyle\sf{(f)\:HCOOH+H_2SO_4\longrightarrow CO_2+SO_2+2H_2O$

$\displaystyle\sf{(g)\:3SiCl_4+16NH_3\longrightarrow Si_3N_4+12NH_4Cl$

$\displaystyle\sf{(h)\:SiCl_4+4C_2H_5OH\longrightarrow Si(OC_2H_5)_4+4HCl$

$\displaystyle\sf{(i)\:2B+6NaOH\longrightarrow2NaBO_2+3H_2+2Na_2O$

$\displaystyle\sf{(j)\:2H_3BO_3\longrightarrow B_2O_3+3H_2O$

Answer 2

Answer:

BN+3H_2O

\displaystyle\sf{(b)\:Na_2B_4O_7+H_2SO_4+H_2O\longrightarrow H_3BO_3+Na_2SO_4

\displaystyle\sf{(c)\:B_2H_6+2NaOH+2H_2O\longrightarrow 2Na[B(OH)_4]+2H_2

\displaystyle\sf{(d)\:B_2H_6+6CH_3OH\longrightarrow 2B(OCH_3)_3+6H_2

\displaystyle\sf{(e)\:2BF_3+3H_2O\longrightarrow H_3BO_3+HBF_4+2HF

\displaystyle\sf{(f)\:HCOOH+H_2SO_4\longrightarrow CO_2+SO_2+2H_2O

\displaystyle\sf{(g)\:3SiCl_4+16NH_3\longrightarrow Si_3N_4+12NH_4Cl

\displaystyle\sf{(h)\:SiCl_4+4C_2H_5OH\longrightarrow Si(OC_2H_5)_4+4HCl

\displaystyle\sf{(i)\:2B+

Explanation:

thank my answers pls inbo x me