Question

plz answer as fast as possibly

Answer 1

$(ix) \\ {9}^{ \frac{5}{2} } - 3 \times {5}^{0} - {( \frac{1}{81} )}^{ - \frac{1}{2} } \\ \\ \bf \: we \: can \: also \: write \: it \: as \: \\ \\ = {(3)}^{2 \times \frac{5}{2} } - 3 \times {5}^{0} - {( \frac{1}{9} )}^{2 \times - \frac{1}{2} } \\ \\ = {3}^{5} - 3 \times {5}^{0} - {( \frac{1}{9} )}^{ - 1} \\ \\ \bf \: as \: we \: know \: that \: \\ \bf \: {( \frac{1}{a} )}^{ - m} = {a}^{m} \\ \\ \bf \: also \\ \bf \: any \: value \: with \: power \: 0 \\ \bf \: equals \: 1 \\ \\ = {3}^{5} - 3 \times 1 - 9 \\ \\ = {3}^{5} - 3 -9 \\ \\ = 243 - 12 \\ \\ = 231$


$(x) \\ {( \frac{1}{4}) }^{ - 2} - 3 \times {(8)}^{ \frac{2}{3} } \times {4}^{0} + {( \frac{9}{16} )}^{ - \frac{1}{2} } \\ \\ = {(4)}^{2} - 3 \times {(2)}^{3 \times \frac{2}{3} } \times 1 + {( \frac{16}{3} )}^{ \frac{1}{2} } \\ \\ = 16 - 3 \times {(2)}^{2} \times 1 + {( \frac{4}{3} )}^{2 \times \frac{1}{2} } \\ \\ = 16 - 3 \times 4 + \frac{4}{3} \\ \\ = 16 - 12 + \frac{4}{3} \\ \\ \frac{48 - 36 + 4}{3} \\ \\ = \frac{16}{3}$

If any doubt, please ask :)